Finding the Polynomial Function f(x) Given Quotient and Remainder
When the Function f(x) is Divided by (x-2), the Quotient is x^2 6x 8 and the Remainder is -1
When we divide the function f(x) by (x-2), we get a quotient of x^2 6x 8 and a remainder of -1. This division can be written in a general form for polynomial division, where the dividend (f(x)) is equal to the divisor (x-2) times the quotient (x^2 6x 8), plus the remainder (-1). The process involves several steps and can be easily understood with some basic algebraic manipulation.
Step-by-Step Solution
Let's break down the steps to find the function f(x) in standard form:
General Formula for Polynomial Division
The general formula for polynomial division can be written as:
f(x) (x-2) (x^2 6x 8) - 1
Expanding the Expression
First, we expand the expression (x-2) (x^2 6x 8) using the distributive property (also known as the FOIL method for binomials, but extended to polynomials here).
Expanding (x-2) (x^2 6x 8) gives us:
x (x^2 6x 8) - 2 (x^2 6x 8)
Simplifying this, we get:
x^3 6x^2 8x - 2x^2 - 12x - 16
Combining like terms:
x^3 4x^2 - 4x - 16
Subtracting the Remainder
Now, we subtract the remainder, which is -1, from our expanded expression.
x^3 4x^2 - 4x - 16 - 1
This simplifies to:
f(x) x^3 4x^2 - 4x - 17
Verification
To verify our result, we use the division formula directly:
Let's write it out step-by-step:
1. Take the function f(x)
2. Divide by (x-2)
[ frac{f(x)}{x-2} x^2 6x 8 - frac{1}{x-2} ]
Multiplying both sides by (x-2) gives:
[ f(x) (x-2)(x^2 6x 8) - 1 ]
Expanding and simplifying:
[ f(x) x^3 4x^2 - 4x - 17 ]
Conclusion
In summary, when the function f(x) is divided by (x-2), the quotient is x^2 6x 8, and the remainder is -1, the polynomial function f(x) in standard form is:
[ f(x) x^3 4x^2 - 4x - 17 ]
Keywords
polynomial function, quotient and remainder, polynomial division
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